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RubyでLeetCodeを解いてみた Reverse Integer

Ruby
leetcode

Posted at 2020-01-17

Given a 32-bit signed integer, reverse digits of an integer.

# @param {Integer} x
# @return {Integer}
def reverse(x)
    if x.positive?
      y = x.to_s.reverse.to_i
    else
      y = x.to_s.reverse.to_i*-1
    end
    return  0 if ( y > 2147483646 || y < -2147483647)
    y
end

rubyはover flowの扱いが特殊みたいで
生々しい実装になってしまいました😀😀😀

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